"linq pick random element" Code Answer's

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Linq - Random Elements

Kenny Nuylla on Jun 05, 2020

var rnd = new Random();
var SelectedPost = q.OrderBy(x => rnd.Next()).Take(1);

Source: stackoverflow.com

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linq pick random element

Important Iguana on Feb 17, 2021

var rand = new Random();
var user = users[rand.Next(users.Count)];

Source: stackoverflow.com

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"linq pick random element" Code Answer's

Linq - Random Elements

linq pick random element

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