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c# create dynamic json
[TestFixture]
public class DynamicJson
{
[Test]
public void Test()
{
dynamic flexible = new ExpandoObject();
flexible.Int = 3;
flexible.String = "hi";
var dictionary = (IDictionary<string, object>)flexible;
dictionary.Add("Bool", false);
var serialized = JsonConvert.SerializeObject(dictionary); // {"Int":3,"String":"hi","Bool":false}
}
}
Source: stackoverflow.com
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