"indexof in c#" Code Answer's
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c sharp index of substring
// To find the index of the first substring in a string use
// 'IndexOf()'
string str = "Hello World!"
str.IndexOf("o"); // Output: 4
// You can give a starting index and a length to search at
str.IndexOf("o", 6, 4); // Output: 7
// To find the last instance of a substring use 'LastIndexOf()'
str.LastIndexOf("o"); // Output: 7
Source: docs.microsoft.com
letter at index of string c#
string s = "hello";
char c = s[1];
// now c == 'e'
Source: stackoverflow.com
c# IndexOf
string word = "Hello";
int where = word.IndexOf("e");
// int where returns index number where the letter "e" is located.
// --0-1-2-3-4-- < Index number
// --H-e-l-l-o-- < Word
// In this case, the letter "e" is located in the index number 1
strinng.indexOf c#
int index = String.IndexOf(char x);
int index = String.IndexOf(string x);
indexof c#
string br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+---";
string br2 = "012345678901234567890123456789012345678901234567890123456789012345678";
string str = "Now is the time for all good men to come to the aid of their country.";
int start;
int at;
int end;
int count;
end = str.Length;
start = end/2;
Console.WriteLine();
Console.WriteLine("All occurrences of 'he' from position {0} to {1}.", start, end-1);
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str);
Console.Write("The string 'he' occurs at position(s): ");
count = 0;
at = 0;
while((start <= end) && (at > -1))
{
// start+count must be a position within -str-.
count = end - start;
at = str.IndexOf("he", start, count);
if (at == -1) break;
Console.Write("{0} ", at);
start = at+1;
}
Console.WriteLine();
/*
This example produces the following results:
All occurrences of 'he' from position 34 to 68.
0----+----1----+----2----+----3----+----4----+----5----+----6----+---
012345678901234567890123456789012345678901234567890123456789012345678
Now is the time for all good men to come to the aid of their country.
The string 'he' occurs at position(s): 45 56
*/
Source: docs.microsoft.com
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