"Random number in C#" Code Answer's

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c# random int

By Plat00nPlat00n on Sep 16, 2020 
Random rnd = new Random();
int number  = rnd.Next(1, 10);

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16

c# random number

By Drab DormouseDrab Dormouse on Oct 20, 2020 
int random_number = new Random().Next(1, 10) // Generates a number between 1 to 10

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21

random number generator c#

By Elated ElandElated Eland on Jan 07, 2020 
Random rnd = new Random();
int month  = rnd.Next(1, 13);  // creates a number between 1 and 12
int dice   = rnd.Next(1, 7);   // creates a number between 1 and 6
int card   = rnd.Next(52);     // creates a number between 0 and 51

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22

c# random generator

By Hello ThereHello There on Oct 28, 2020 
// One string will be randomly picked and displayed 
Random rnd = new Random();
string[] secOptions = {"string one", "string two", "string three"};
int randomNuber = rnd.Next(0, 3);
string secText = secOptions[randomNuber];
Console.WriteLine(secText);

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7

how to generate random numbers in c#

By Joyous JackalJoyous Jackal on Jul 03, 2020 
//works in visual studio for unity
int randomNumber = UnityEngine.Random.Range(1, 100);  //Random number between 1 and 99

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13

Random number in C#

By Worrisome WeaselWorrisome Weasel on Jan 29, 2021 
The following code return a random number lower than 1000
  
    int num = random.Next(1000);  

The following code returns a random number between the min and the max range.

    // Instantiate random number generator.  
    private readonly Random _random = new Random();  
      
    // Generates a random number within a range.      
    public int RandomNumber(int min, int max)  
    {  
      return _random.Next(min, max);  
    }

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-1

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C# answers related to "Random number in C#"

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C# queries related to "Random number in C#"

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