How to create a one-second delay in Java?
If we use the system class, then the easiest way to create a delay in java - is to call the static method Thread. sleep(int). It is this method of sleep that will make us pause. The method takes an integer number of milliseconds as a parameter. In general, try to avoid using Thread. sleep() for delays like this. While it creates a one-second delay, what it does not do is give other codes an opportunity to run.
java sleep 1 sec
on Jan 01, 1970
function delay(time) {
return new Promise(resolve => setTimeout(resolve, time));
}
delay(1000).then(() => console.log('ran after 1 second1 passed'));
0
java pause 1 second
on Jan 01, 1970
//deprecated in main thread:
try {
Thread.sleep(1000);//time is in ms (1000 ms = 1 second)
} catch (InterruptedException e) {e.printStackTrace();}
//please use bellow instead:
Timer timer = new Timer();
timer.schedule(new TimerTask() {
@Override
public void run() {
//what you want to do
}
}, 1000);//wait 1000ms before doing the action
0
java delay
on Jan 01, 1970
Syntax :
=========================================================
Thread.sleep(1000); // 1000 milliseconds.. |
=========================================================
int i=0;
for(;;){
Thread.sleep(2000); // set time delay to 2 seconds..
System.out.println(i++); // output : every output will display after 2 seconds..
}
0
sleep() java
on Jan 01, 1970
import java.util.concurrent.TimeUnit
try {
TimeUnit.SECONDS.sleep(1);
}
catch (Exception e) {
System.out.println("Oops! Something went wrong!")
}
0
java sleep 1 second
on Jan 01, 1970
import java.util.Date;
public class JavaHungry {
public static void main(String args[]) {
try
{
System.out.println("Start of delay: "+ new Date());
// Delay for 7 seonds
Thread.sleep(7000);
System.out.println("End of delay: "+ new Date());
}
catch(InterruptedException ex)
{
ex.printStackTrace();
}
}
}
0
You should use something like the DelayQueue class that's included with the standard Java library and found in java.util.concurrent.
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