jquery get url parameter” Code Answer’s
Occasionally, we are required to acquire values by the query string in the URL on the search engine uniform resource locator (URL). But there arose a question that in which way we have to acquire the JavaScript or jQuery as we are required them on the client-oriented. There are four methods for acquiring values from the query framework.URLSearchParams is the build in intersection by the newest search engines by different ways to acquire and operate values.
jquery get url
on Jan 01, 1970
var currentURL = $(location).attr('href');
var currentURL = window.location.href;0
how to get url parameter using jquery or plain javascript
on Jan 01, 1970
var getUrlParameter = function getUrlParameter(sParam) {
var sPageURL = window.location.search.substring(1),
sURLVariables = sPageURL.split('&'),
sParameterName,
i;
for (i = 0; i < sURLVariables.length; i++) {
sParameterName = sURLVariables[i].split('=');
if (sParameterName[0] === sParam) {
return typeof sParameterName[1] === undefined ? true : decodeURIComponent(sParameterName[1]);
}
}
return false;
};
And this is how you can use this function assuming the URL is,
http://dummy.com/?technology=jquery&blog=jquerybyexample.
var tech = getUrlParameter('technology');
var blog = getUrlParameter('blog');0
get param from url jquery
on Jan 01, 1970
var getUrlParameter = function getUrlParameter(sParam) {
var sPageURL = window.location.search.substring(1),
sURLVariables = sPageURL.split('&'),
sParameterName,
i;
for (i = 0; i < sURLVariables.length; i++) {
sParameterName = sURLVariables[i].split('=');
if (sParameterName[0] === sParam) {
return typeof sParameterName[1] === undefined ? true : decodeURIComponent(sParameterName[1]);
}
}
return false;
};
0
jquery get parameter from url
on Jan 01, 1970
(function($) {
$.QueryString = (function(a) {
if (a == "") return {};
var b = {};
for (var i = 0; i < a.length; ++i)
{
var p=a[i].split('=');
if (p.length != 2) continue;
b[p[0]] = decodeURIComponent(p[1].replace(/\+/g, " "));
}
return b;
})(window.location.search.substr(1).split('&'))
})(jQuery);
// Usage
var param = jQuery.QueryString["param"];0
Hope so that you have got your answer.Please let us inform about your valuable suggestion in the comment section
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