"object destructuring default value" Code Answer's
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destructuring objects
({ a, b } = { a: 10, b: 20 });
console.log(a); // 10
console.log(b); // 20
// Stage 4(finished) proposal
({a, b, ...rest} = {a: 10, b: 20, c: 30, d: 40});
console.log(a); // 10
console.log(b); // 20
console.log(rest); // {c: 30, d: 40}
Source: developer.mozilla.org
array destructuring
//Without destructuring
const myArray = ["a", "b", "c"];
const x = myArray[0];
const y = myArray[1];
console.log(x, y); // "a" "b"
//With destructuring
const myArray = ["a", "b", "c"];
const [x, y] = myArray; // That's it !
console.log(x, y); // "a" "b"
object destructuring
let a, b, rest;
[a, b] = [10, 20];
console.log(a);
// expected output: 10
console.log(b);
// expected output: 20
[a, b, ...rest] = [10, 20, 30, 40, 50];
console.log(rest);
// expected output: Array [30,40,50]
Source: developer.mozilla.org
js object destructuring with defaults
// Taken from top stack overflow answer
const { dogName = 'snickers' } = { dogName: undefined }
console.log(dogName) // what will it be? 'snickers'!
const { dogName = 'snickers' } = { dogName: null }
console.log(dogName) // what will it be? null!
const { dogName = 'snickers' } = { dogName: false }
console.log(dogName) // what will it be? false!
const { dogName = 'snickers' } = { dogName: 0 }
console.log(dogName) // what will it be? 0!
object destructuring default value
let a, b;
[a=5, b=7] = [1];
console.log(a); // 1
console.log(b); // 7
Source: developer.mozilla.org
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