"levenshtein distance" Code Answer's
You're definitely familiar with the best coding language Python that developers use to develop their projects and they get all their queries like "levenshtein distance" answered properly. Developers are finding an appropriate answer about levenshtein distance related to the Python coding language. By visiting this online portal developers get answers concerning Python codes question like levenshtein distance. Enter your desired code related query in the search bar and get every piece of information about Python code related question on levenshtein distance.
levenshtein distance
Katonkel
on May 23, 2021
def levenshtein(a, b):
m = [[*range(len(a) + 1)] for _ in range(len(b) + 1)]
for i in range(len(b) + 1):
m[i][0] = i
for i in range(1, len(b) + 1):
for j in range(1, len(a) + 1):
m[i][j] = min(m[i-1][j] + 1, m[i][j-1] + 1, m[i-1][j-1] + (b[i-1] != a[j-1]))
return m[-1][-1]levenshtein distance
Katonkel
on May 24, 2021
package main
import "fmt"
// levenshtein distance in Golang
func levenshtein(str1, str2 []rune) int {
s1len := len(str1)
s2len := len(str2)
column := make([]int, len(str1)+1)
for y := 1; y <= s1len; y++ {
column[y] = y
}
for x := 1; x <= s2len; x++ {
column[0] = x
currkey := x - 1
for y := 1; y <= s1len; y++ {
oldkey := column[y]
incr := 0
if str1[y-1] != str2[x-1] {
incr = 1
}
column[y] = min3(column[y]+1, column[y-1]+1, currkey+incr)
currkey = oldkey
}
}
return column[s1len]
}
func min3(a, b, c int) int {
if a < b {
if a < c { return a }
} else {
if b < c { return b }
}
return c
}
func main(){
var str1, str2 = []rune("Monday"), []rune("Friday")
fmt.Printf("Distance between Monday and Friday = %d\n", levenshtein(str1, str2)) // 3
}levenshtein distance
Katonkel
on May 24, 2021
fn levenshtein(word1: &str, word2: &str) -> usize {
let s = word1.chars().collect::<Vec<_>>();
let t = word2.chars().collect::<Vec<_>>();
let slength = s.len() + 1;
let tlength = t.len() + 1;
let mut m = vec![vec![0]];
for i in 1..slength { m[0].push(i); }
for j in 1..tlength { m.push(vec![j]); }
for j in 1..tlength {
for i in 1..slength {
let tmp: usize = if s[i-1] == t[j-1] {
m[j-1][i-1]
} else {
1 + std::cmp::min(
std::cmp::min(m[j][i-1], m[j-1][i])
, m[j-1][i-1])
};
m[j].push(tmp);
}
}
m[tlength-1][slength-1]
}
fn main() {
println!("{}", levenshtein("Monday", "Friday")); // 3
}levensthein distance
Katonkel
on May 24, 2021
function levenshtein(s, t) {
if(s.length === 0) return t.length;
if(t.length === 0) return s.length;
let m = new Array(s.length + 1).fill(0).map(
(_, i) => new Array(t.length + 1).fill(0).map(
(_,j) => i*j ? 0 : i+j
)
)
for(let i = 1; i <= s.length; i++) {
for(let j = 1; j <= t.length; j++) {
if(s[i - 1] === t[j - 1]) {
m[i][j] = m[i-1][j-1]
} else {
m[i][j] = Math.min(m[i - 1][j - 1], m[i - 1][j], m[i][j - 1]) + 1
}
}
}
return m[s.length][t.length]
}
console.log("Distance between Monday and Friday = %d\n", levenshtein("Monday", "Friday")); // 3All those coders who are working on the Python based application and are stuck on levenshtein distance can get a collection of related answers to their query. Programmers need to enter their query on levenshtein distance related to Python code and they'll get their ambiguities clear immediately. On our webpage, there are tutorials about levenshtein distance for the programmers working on Python code while coding their module. Coders are also allowed to rectify already present answers of levenshtein distance while working on the Python language code. Developers can add up suggestions if they deem fit any other answer relating to "levenshtein distance". Visit this developer's friendly online web community, CodeProZone, and get your queries like levenshtein distance resolved professionally and stay updated to the latest Python updates.
