"how to get the date diff of 2 dates in the same fieldin sql server" Code Answer's
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how to get the date diff on once field in sql server
SELECT t1.OrderNo,DATEDIFF(day,t1.LoadedStartDate,t2.LoadedStartDate)
FROM UnnamedTableFromQuestion t1
INNER JOIN
UnnamedTableFromQuestion t2
on
t1.OrderNo = t2.OrderNo
WHERE t1.OpNo = 1 and
t2.OpNo = 4
////////////////////////////////////////////////////////////////
select cur.unique_id_field, cur.seq_no, cur.date_created ,
datediff(second, prv.date_created, cur.date_created) as diff_in_seconds
from yourtable as cur
join yourtable as prv
on cur.seq_no = prv.seq_no + 1;
Source: stackoverflow.com
how to get the date diff of 2 dates in the same fieldin sql server
WITH Partitioned AS( SELECT *, ROW_NUMBER() OVER (PARTITION BY cu_id, date ORDER BY cu_id, date) AS RowNumber FROM @Table) SELECT *, CASE WHEN RowNumber > 1 THEN 0 ELSE COALESCE(DATEDIFF(DAY, (SELECT MAX(date) FROM @Table WHERE date < a.date AND cu_id = a.cu_id), a.date), 0) END AS Days_betweenFROM Partitioned a
Source: www.sqlteam.com
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