"MySQL top percent" Code Answer's
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MySQL top percent
SELECT * FROM prices WHERE price >= (SELECT price FROM prices p1 WHERE (SELECT count(*) FROM prices p2 WHERE p2.price >= p1.price) <= (SELECT 0.1 * count(*) FROM prices) );
MySQL top percent
SELECT price FROM prices p1 WHERE (SELECT count(*) FROM prices p2 WHERE p2.price >= p1.price) <= (SELECT 0.1 * count(*) FROM prices) );
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