"MySQL top percent" Code Answer's
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MySQL top percent
SELECT * FROM prices WHERE price >= (SELECT price FROM prices p1 WHERE
(SELECT count(*) FROM prices p2 WHERE p2.price >= p1.price) <=
(SELECT 0.1 * count(*) FROM prices)
);
Source: stackoverflow.com
MySQL top percent
SELECT price FROM prices p1 WHERE
(SELECT count(*) FROM prices p2 WHERE p2.price >= p1.price) <=
(SELECT 0.1 * count(*) FROM prices)
);
Source: stackoverflow.com
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