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DATEDIFF minute postgres

By MatteowebMatteoweb on Feb 25, 2020
  -- Difference between Dec 30, 2011 08:54:55 and  Dec 30, 2011 08:56:10 in minutes
  SELECT (DATE_PART('day', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp) * 24 * 60 + 
               DATE_PART('hour', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp)) * 60 +
               DATE_PART('minute', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp);
  -- Result: 1
  -- Time only
  SELECT DATE_PART('hour', '08:56:10'::time - '08:54:55'::time) * 60 +
              DATE_PART('minute', '08:56:10'::time - '08:54:55'::time);
  -- Result: 1

Source: www.sqlines.com

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postgres time difference in minutes

By riffrazorriffrazor on Feb 07, 2020
   CREATE OR REPLACE FUNCTION DateDiff (units VARCHAR(30), start_t TIME, end_t TIME) 
     diff_interval INTERVAL; 
     diff INT = 0;
     -- Minus operator for TIME returns interval 'HH:MI:SS'  
     diff_interval = end_t - start_t;
     diff = DATE_PART('hour', diff_interval);
     IF units IN ('hh', 'hour') THEN
       RETURN diff;
     END IF;
     diff = diff * 60 + DATE_PART('minute', diff_interval);
     IF units IN ('mi', 'n', 'minute') THEN
        RETURN diff;
     END IF;
     diff = diff * 60 + DATE_PART('second', diff_interval);
     RETURN diff;
   $$ LANGUAGE plpgsql;

Source: www.sqlines.com

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