"c++ check if the number is equal to the sum of its divisors excluding itself" Code Answer's
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c++ check if the number is equal to the sum of its divisors excluding itself
// not my code but I found it very useful so I just pasted it
// in order to help others
int i, num, div, sum=0;
cout << "Enter the number to be checked : ";
cin >> num;
for (i=1; i < num; i++)
{
div = num % i;
if (div == 0)
sum = sum + i;
}
if (sum == num)
cout << "\n" << num <<" is a perfect number.";
else
cout << "\n" << num <<" is not a perfect number.";
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