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excel vba string to binary
'VBA function to convert text to a binary string representation:
Public Function TextToBinaryString$(s$)
Dim c&, i&, lo&, bin$(0 To 255), d() As Byte
Const ZEROS$ = "00000000"
For c = 0 To 255
bin(c) = ZEROS
If c And 1& Then MidB$(bin(c), 15) = "1"
If c And 2& Then MidB$(bin(c), 13) = "1"
If c And 4& Then MidB$(bin(c), 11) = "1"
If c And 8& Then MidB$(bin(c), 9) = "1"
If c And 16& Then MidB$(bin(c), 7) = "1"
If c And 32& Then MidB$(bin(c), 5) = "1"
If c And 64& Then MidB$(bin(c), 3) = "1"
If c And 128& Then MidB$(bin(c), 1) = "1"
Next
d = s
lo = 1
TextToBinaryString = Space$(LenB(s) * 8)
For i = 0 To LenB(s) - 1 Step 2
Mid$(TextToBinaryString, lo) = bin(d(i + 1))
Mid$(TextToBinaryString, lo + 8) = bin(d(i))
lo = lo + 16
Next
End Function
'------------------------------------------------------------------------------
MsgBox TextToBinaryString("Hi") '<--displays: 00000000010010000000000001101001
Source: academy.excelhero.com
excel vba binary string to long
'Fast VBA function to converst binary string to a Long Integer:
Function BitsToLong&(bits$)
Dim i&
Static b() As Byte
If LenB(bits) > 64 Then Exit Function
If LenB(bits) = 64 Then
b = bits
Else
b = String$(32 - Len(bits), "0") & bits
End If
For i = 2 To 62 Step 2
BitsToLong = 2 * BitsToLong Or (b(i) Xor 48)
Next
If (b(0) Xor 48) Then BitsToLong = BitsToLong Or &H80000000
End Function
'-----------------------------------------------------------------------------
MsgBox BitsToLong("1") '<--displays: 1
MsgBox BitsToLong("10") '<--displays: 2
MsgBox BitsToLong("0110") '<--displays: 6
MsgBox BitsToLong("0100101") '<--displays: 37
MsgBox BitsToLong("100000000000000000000") '<--displays: 1048576
MsgBox BitsToLong("11111111111111111111111111111111") '<--displays: -1
Source: academy.excelhero.com
excel vba binary string to short integer
'Extremely fast VBA function to convert a binary string to a 16-bit Integer:
Function BitsToInteger%(bits$)
Dim i&
Static b() As Byte
If LenB(bits) > 32 Then Exit Function
If LenB(bits) = 32 Then
b = bits
Else
b = String$(16 - Len(bits), "0") & bits
End If
For i = 2 To 30 Step 2
BitsToInteger = 2 * BitsToInteger Or (b(i) Xor 48)
Next
If (b(0) Xor 48) Then BitsToInteger = BitsToInteger Or &H8000
End Function
'Example:
MsgBox BitsToInteger("1111111111111111") '<--displays: -1
MsgBox BitsToInteger("0111111111111111") '<--displays: 32767
Source: academy.excelhero.com
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