“regex match any number of digits” Code Answer’s
We use \d for matching any number ranging from 0 to 9 in regex and it will match from 0 to 9 any digit number.
The means of \d is or 0 to 9 any digit number.
The smart version is used instead of writing 0123456789.
regex numeric digits
on Jan 01, 1970
' Needs reference "Microsoft VBScript Regular Expressions 5.5"
Dim rRegex As Object
Set rRegex = CreateObject("VBScript.RegExp")
rRegex.Pattern = "[0-9]{8,9}" ' 8 or 9 numbers
MsgBox rRegex.test("12345678") ' True
rRegex.Pattern = "[0-9]+" ' Numeric of any size
MsgBox rRegex.test("12345") ' True0
regex match any number of digits
on Jan 01, 1970
For matching an integer number of one single char/digit, specify:
[0-9]
But for matching any number of more than one char/digit; add "+":
[0-9]+
Example for matching hour with minutes of HH:MM format in a file:
grep "[0-9]\+\:[0-9]\+" file.txt0
Above I explained how regex matches any number of digits and I hope that this will be proved helpful to you.
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