"Given a list of file paths, print them out in a hierarchal way" Code Answer's

Given a list of file paths, print them out in a hierarchal way

By Disgusted Dogfish on May 11, 2020

var data = 'three-dxf-master/' +
           '\nfoobar/fumm' +
           '\nthree-dxf-master/.DS_Store' +
           '\nthree-dxf-master/.gitignore' +
           '\nthree-dxf-master/LICENSE' +
           '\nthree-dxf-master/README.md' +
           '\nthree-dxf-master/bower.json' +
           '\nthree-dxf-master/bower_components/' +
           '\nthree-dxf-master/bower_components/.DS_Store' +
           '\nthree-dxf-master/bower_components/dxf-parser/';

function parseData(data) {
  var records = data.split(/\n/);
  var result = records.reduce(function(acc, record) {
    var fields = record.match(/[^\/]+\/?/g) || [];
    var currentDir = acc;
       
    fields.forEach(function (field, idx) {

      // If field is a directory...
      if (/\/$/.test(field)) {
        
        // If first one and not an existing directory, add it
        if (idx == 0) {
          if (!(field in currentDir)) {
            currentDir[field] = [];
          }
          
          // Move into subdirectory
          currentDir = currentDir[field];
          
        // If not first, see if it's a subdirectory of currentDir
        } else {
          // Look for field as a subdirectory of currentDir
          var subDir = currentDir.filter(function(element){
            return typeof element == 'object' && element[field];
          })[0];
          
          // If didn't find subDir, add it and set as currentDir
          if (!subDir) {
            var t = Object.create(null);
            t[field] = [];
            currentDir.push(t);
            currentDir = t[field];
            
          // If found, set as currentDir
          } else {
            currentDir = subDir[field];
          }
        }
        
      // Otherwise it's a file. Make sure currentDir is a directory and not the root
      } else {
        if (Array.isArray(currentDir)) {
          currentDir.push(field);
          
        // Otherwise, must be at root where files aren't allowed
        } else {
          throw new Error('Files not allowed in root: ' + field);
        }
      }
    });
    
    return acc;
    
  }, Object.create(null));
  return result;
}

//console.log(JSON.stringify(parseData(data)));
console.log(parseData(data));

Source: stackoverflow.com

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