"sp to create unique id if a new value is found" Code Answer's
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sp to create unique id if a new value is found
CREATE TRIGGER TLA_Items_Adjust
ON dbo.TLA_Items
FOR INSERT
AS
BEGIN
UPDATE t
SET t.UniqueID = i.UniqueID + CAST(t.IdentityColumn AS varchar(10))
FROM dbo.TLA_Items AS t
INNER JOIN inserted AS i
ON t.IdentityColumn = i.IdentityColumn
;
END
Source: stackoverflow.com
sp to create unique id if a new value is found
CREATE PROCEDURE [TLA_CreateItem]
@SiteReference varchar(50)
,@ItemID varchar(4)
,@NewUniqueID varchar(68) OUTPUT
AS
BEGIN
DECLARE @GeneratedUniqueID TABLE (UniqueID varchar(68));
INSERT INTO dbo.[TLA_Items] ([ItemID], [UniqueID])
OUTPUT inserted.UniqueID INTO @GeneratedUniqueID (UniqueID)
VALUES (@ItemID, @ItemID + @SiteReference);
SELECT @NewUniqueID = UniqueID FROM @GeneratedUniqueID;
SELECT @NewUniqueID;
END
Source: stackoverflow.com
sp to create unique id if a new value is found
CREATE PROCEDURE [TLA_CreateItem]
@SiteReference varchar(50)
,@ItemID varchar(4)
,@NewUniqueID varchar(68) OUTPUT
AS
BEGIN
INSERT INTO dbo.[TLA_Items] ([ItemID], [UniqueID])
VALUES (@ItemID, @ItemID + @SiteReference);
SELECT @NewUniqueID = UniqueID
FROM dbo.TLA_Items
WHERE IdentityColumn = SCOPE_IDENTITY();
SELECT @NewUniqueID;
END
Source: stackoverflow.com
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