"2d array c++" Code Answer's
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2d array c++
int a[2][3]= {
{1, 2, 3},
{4, 5, 6}
};
cout << a[1][1]; // Output is 5
declaring 2d dynamic array c++
int** arr = new int*[10]; // Number of Students
int i=0, j;
for (i; i<10; i++)
arr[i] = new int[5]; // Number of Courses
/*In line[1], you're creating an array which can store the addresses
of 10 arrays. In line[4], you're allocating memories for the
array addresses you've stored in the array 'arr'. So it comes out
to be a 10 x 5 array. */
c++ code to write 2d array
#include <iostream>
using namespace std;
int main(){
int n,m;
int a[n][m];
cin >> n >>m;
for ( int i=0; i<n; i++){
for (int j=0; j<m; j++){
cin >> a[i][j];
}
}
for ( int x=0; x<n; x++){
for (int y=0; y<m; y++){
cout << "a[" << x << "][" << y << "]: ";
cout << a[x][y] << endl;
}
}
return 0;
}
c++ 2D vectors
int main()
{
int row = 5; // size of row
int colom[] = { 5, 3, 4, 2, 1 };
vector<vector<int> > vec(row); // Create a vector of vector with size equal to row.
for (int i = 0; i < row; i++) {
int col;
col = colom[i];
vec[i] = vector<int>(col); //Assigning the coloumn size of vector
for (int j = 0; j < col; j++)
vec[i][j] = j + 1;
}
for (int i = 0; i < row; i++) {
for (int j = 0; j < vec[i].size(); j++)
cout << vec[i][j] << " ";
cout << endl;
}
}
get elements of 2d array c++
#include <array>
2 #include <iostream>
3
4 using namespace std;
5
6 //remember const!
7 const int ROWS = 2;
8 const int COLS = 3;
9
10 void printMatrix(array<array<int, COLS>, ROWS> matrix){
11 //for each row
12 for (int row = 0; row < matrix.size(); ++row){
13 //for each element in the current row
14 for (int col = 0; col < matrix[row].size(); ++col){
15 cout << matrix[row][col] << ' ';
16 }
17 cout << endl;
18 }
19 }
get elements of 2d array c++
void printMatrix(array<array<int, COLS>, ROWS> matrix){
for (auto row : matrix){
//auto infers that row is of type array<int, COLS>
for (auto element : row){
cout << element << ' ';
}
cout << endl;
}
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