"merge sort" Code Answer's

merge sort

By ujjwal sotra on May 27, 2021

//merge sort
#include <iostream>

using namespace std;
void merge(int arr[],int start,int mid,int end)
{
    int n1=mid-start+1;
    int n2=end-mid;
    int l[n1],m[n2];
    for(int i=0;i<n1;i++)
    {
        l[i]=arr[start+i];
    }
    for(int j=0;j<n2;j++)
    {
        m[j]=arr[mid+1+j];
    }
    int i=0;
    int j=0;
    int k=start;
    while(i<n1&&j<n2)
    {
        if(l[i]<m[j])
        {
            arr[k]=l[i];
            k++;
            i++;
        }
        else
        {
            arr[k]=m[j];
            k++;
            j++;
        }
    }
    while(i<n1)
    {
        arr[k]=l[i];
        k++;
        i++;
    }
    while(j<n2)
    {
        arr[k]=m[j];
        k++;
        j++;
    }
}
void mergesort(int arr[],int start,int end)
{
    if(start<end)
    {
        int mid=(start+end)/2;
        mergesort(arr,start,mid);
        mergesort(arr,mid+1,end);
        merge(arr,start,mid,end);
    }
}
void display(int arr[],int n)
{
    for(int i=0;i<n;i++)
    {
        cout<<arr[i]<<" ";
    }
    cout<<endl;
}

int main()
{
    int n;
    cout<<"enter the size of the array:"<<endl;
    cin>>n;
    cout<<"enter the elements of the array:"<<endl;
    int arr[n];
    for(int i=0;i<n;i++)
    {
        cin>>arr[i];
    }
    cout<<"array as it is:"<<endl;
    display(arr,n);
    cout<<"sorted array:"<<endl;
    mergesort(arr,0,n-1);
    display(arr,n);
    return 0;
}

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Merge sort

By Itchy Impala on May 31, 2021

class Sort 
{
    void merge(int arr[], int left, int middle, int right)
    {
        int low = middle - left + 1;                    //size of the left subarray
        int high = right - middle;                      //size of the right subarray
 
        int L[] = new int[low];                             //create the left and right subarray
        int R[] = new int[high];

        int i = 0, j = 0;
 
        for (i = 0; i < low; i++)                               //copy elements into left subarray
        {
            L[i] = arr[left + i];
        }
        for (j = 0; j < high; j++)                              //copy elements into right subarray
        {
            R[j] = arr[middle + 1 + j];
        }
        
 
        int k = left;                                           //get starting index for sort
        i = 0;                                             //reset loop variables before performing merge
        j = 0;

        while (i < low && j < high)                     //merge the left and right subarrays
        {
            if (L[i] <= R[j]) 
            {
                arr[k] = L[i];
                i++;
            }
            else 
            {
                arr[k] = R[j];
                j++;
            }
            k++;
        }
 
        while (i < low)                             //merge the remaining elements from the left subarray
        {
            arr[k] = L[i];
            i++;
            k++;
        }
 
        while (j < high)                           //merge the remaining elements from right subarray
        {
            arr[k] = R[j];
            j++;
            k++;
        }
    }
 

    void mergeSort(int arr[], int left, int right)       //helper function that creates the sub cases for sorting
    {
        int middle;
        if (left < right) {                             //sort only if the left index is lesser than the right index (meaning that sorting is done)
            middle = (left + right) / 2;
 
            mergeSort(arr, left, middle);                    //left subarray
            mergeSort(arr, middle + 1, right);               //right subarray
 
            merge(arr, left, middle, right);                //merge the two subarrays
        }
    }
 
    void display(int arr[])                 //display the array
    {  
        for (int i=0; i<arr.length; ++i) 
        {
            System.out.print(arr[i]+" ");
        } 
    } 

    public static void main(String args[])
    {
        int arr[] = { 9, 3, 1, 5, 13, 12 };
        Sort ob = new Sort();
        ob.mergeSort(arr, 0, arr.length - 1);
        ob.display(arr);
    }
}

Source: favtutor.com

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merge sort

By adriancmiranda on May 31, 2020

// @see https://www.youtube.com/watch?v=es2T6KY45cA&vl=en
// @see https://www.cs.usfca.edu/~galles/visualization/ComparisonSort.html

function merge(list, start, midpoint, end) {
    const left = list.slice(start, midpoint);
    const right = list.slice(midpoint, end);
    for (let topLeft = 0, topRight = 0, i = start; i < end; i += 1) {
        if (topLeft >= left.length) {
            list[i] = right[topRight++];
        } else if (topRight >= right.length) {
            list[i] = left[topLeft++];
        } else if (left[topLeft] < right[topRight]) {
            list[i] = left[topLeft++];
        } else {
            list[i] = right[topRight++];
        }
    }
}

function mergesort(list, start = 0, end = undefined) {
    if (end === undefined) {
        end = list.length;
    }
    if (end - start > 1) {
        const midpoint = ((end + start) / 2) >> 0;
        mergesort(list, start, midpoint);
        mergesort(list, midpoint, end);
        merge(list, start, midpoint, end);
    }
    return list;
}

mergesort([4, 7, 2, 6, 4, 1, 8, 3]);

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merge sort

By Outstanding Oyster on Jan 16, 2021

# Python3 recursive merge sort algorithm -> O(n*log(n))
def merge_sort(A):
    def merge(l, r):
        i = j = 0
        n = []  # merging container
        while i < len(l) or j < len(r):

            # if no more elements to the right,
            # add remaining left elements
            if i == len(l):
                n.extend(r[j:])
                break

            # if no more elements to the left,
            # add remaining right elements
            if j == len(r):
                n.extend(l[i:])
                break

            # if elements left on both sides,
            # add smaller element
            a, b = l[i], r[j]
            if a < b:
                n.append(a)
                i += 1
            else:
                n.append(b)
                j += 1

        return n

    # divide list down to single-elements
    s = len(A)
    if s > 1:
        s //= 2
        l = merge_sort(A[:s])  # split left
        r = merge_sort(A[s:])  # split right
        return merge(l, r)  # merge sides in order
    else:
        return A

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merge sort

By Ashamed Alligator on Jun 17, 2021

Given array is 
12 11 13 5 6 7 
Sorted array is 
5 6 7 11 12 13

Source: www.geeksforgeeks.org

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merge sort

By Successful Swan on May 03, 2021

Step 1 − if it is only one element in the list it is already sorted, return.
Step 2 − divide the list recursively into two halves until it can no more be divided.
Step 3 − merge the smaller lists into new list in sorted order.

Source: www.tutorialspoint.com

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