"reverse() in c++" Code Answer's
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c++ reverse vector
#include <bits/stdc++.h> // Vector
#include <algorithm> // Reverse
using namespace std;
int main()
{
vector<int> nums{4,1,2,1,2};
reverse(nums.begin(), nums.end());
return 0;
}
reverse an array in cpp
#include<iostream>
using namespace std;
int main()
{
int n=3;
int arr[]={1,2,3,4};
while (n>=0)
{
cout<<arr[n];
n--;
}
return 0;
}
reverse an array in c++
#include <iostream>
using namespace std;
int main()
{ // While loop
const int SIZE = 9;
int arr [SIZE];
cout << "Enter numbers: \n";
for (int i = 0; i < SIZE; i++)
cin >> arr[i];
for (int i = 0; i < SIZE; i++)
cout << arr[i] << "\t";
cout << endl;
cout << "Reversed Array:\n";
int temp, start = 0, end = SIZE-1;
while (start < end)
{
temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
for (int i = 0; i < SIZE; i++)
cout << arr[i] << "\t";
cout << endl;
return 0;
}
c++ reverse array
int arr[5] = {1, 2, 3, 4, 5}; //Initialize array
for(int i = 0; i < size(arr); i++) {
//Create temporary variable to hold current value in array
int temp = arr[i];
//Set the current value in the array to the mirrored value in array
arr[i] = arr[size(arr) - 1 - i];
//Set mirrored value in array to temp, swapping the two numbers
arr[size(arr) - 1 - i] = temp;
}
c++ reverse part of vector
//Reverse vector partially (from index x to index y)
reverse(v.begin()+x, v.begin()+y+1);
reverse() in c++
#include <iostream>
#include <algorithm>
#include <vector>
#include <iterator>
using namespace std;
int main()
{
vector<int>a = {11,22,33,44,99,55};
reverse(a.begin(), a.end());
auto it = a.begin();
for(it= a.begin(); it!=a.end(); it++){
cout << *it << ' ';
}
}
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