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operator overloading in c++

By GaLGaL on Nov 17, 2020 
ostream &operator<<(ostream &output, const MyClass &myObject)
{ 
  output << "P : " << myObject.property;
  return output;            
}

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4

Explain operator overloading with an example.

By Bing JuniorBing Junior on Nov 22, 2020 
In C++, we can change the way operators work for user-defined types like objects and structures. This is known as operator overloading. For example,

Suppose we have created three objects c1, c2 and result from a class named Complex that represents complex numbers.

Since operator overloading allows us to change how operators work, we can redefine how the + operator works and use it to add the complex numbers of c1 and c2 by writing the following code:

result = c1 + c2;
instead of something like

result = c1.addNumbers(c2);
This makes our code intuitive and easy to understand.

Note: We cannot use operator overloading for fundamental data types like int, float, char and so on.

Syntax for C++ Operator Overloading
To overload an operator, we use a special operator function.

class className {
    ... .. ...
    public
       returnType operator symbol (arguments) {
           ... .. ...
       } 
    ... .. ...
};

Source: www.programiz.com

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2

Operator overloading in C++ Programming

By @kkithool@kkithool on May 09, 2020 
#include <iostream>
using namespace std;

class Test
{
   private:
      int count;

   public:
       Test(): count(5){}

       void operator ++() 
       { 
          count = count+1; 
       }
       void Display() { cout<<"Count: "<<count; }
};

int main()
{
    Test t;
    // this calls "function void operator ++()" function
    ++t;    
    t.Display();
    return 0;
}

Source: www.programiz.com

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2

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