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c++ evaluate expression

By Shiny SkimmerShiny Skimmer on May 13, 2020
#include "tinyexpr.h"
#include <stdio.h>

int main()
{
    double answer = te_interp("3*2+4*1+(4+9)*6", 0);
    printf("Answer is %f\n", answer);
    return 0;
}

Source: stackoverflow.com

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