"static in in c++" Code Answer's
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static variable in c++
/*
this example show where and how
static variables are used
*/
#include <iostream>
#include <string>
//doing "using namespace std" is generally a bad practice, this is an exception
using namespace std;
class Player
{
int health = 200;
string name = "Name";
//static keyword
static int count = 0;
public:
//constructor
Player(string set_name)
:name{set_name}
{
count++;
}
//destructor
~Player()
{
count--;
}
int how_many_player_are_there()
{
return count;
}
};
int main()
{
Player* a = new Player("some name");
cout << "Player count: " << *a.how_many_player_are_there() << std::endl;
Player* b = new Player("some name");
cout << "Player count: " << *a.how_many_player_are_there() << std::endl;
delete a;
cout << "Player count: " << *b.how_many_player_are_there() << std::endl;
}
/*output:
1
2
1
*/
static inside local scope in c++
#include<iostream>
//Singleton class is a class having only one instance
class SingleTon {
public:
static SingleTon& Get() {
static SingleTon s_Instance;
return s_Instance;
}//there is only one instance of static functions and variables across all instances of class
void Hellow() {}
};
void Increment() {
int i = 0;//The life time of variable is limited to the function scope
i++;
std::cout << i << std::endl;
};//This will increment i to one and when it will reach the end bracket the lifetime of var will get destroyed
void IncrementStaticVar() {
static int i = 0;//The life time of this var is = to program
i++;
std::cout << i << std::endl;
}//This will increment i till the program ends
int main() {
Increment();//output 1
Increment();//output 1
Increment();//output 1
IncrementStaticVar();// output 2
IncrementStaticVar();// output 3
IncrementStaticVar();// output 4
IncrementStaticVar();// output 5
SingleTon::Get();
std::cin.get();
}
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