"the first n approximations of number pi in c++" Code Answer's
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the first n approximations of number pi in c++
/* This program calculates the first n approximations of the number pi
from the infinite series
pi = 4 - 4/3 + 4/5 - 4/7 + 4/9 - 4/11 + ...
All the approximations and displayed
*/
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int n{ 170000 }, index=-1;
double approximation{ 1 };
cout << "approximation 0: 4" << endl;
for (int i = 1; i <= n; i++) {
approximation += pow(-1, i) / static_cast<double>(2 * i + 1);
cout << "approximation " << i << ": ";
cout << setprecision(9) << setw(10) << left << fixed; // do not remove fixed to see all 9 decimal places
cout << 4 * approximation << endl;
if (static_cast<int>(4 * approximation * 100000) == 314159 and index == -1) {
cout << "The " << i << "th approximation begins with 3.14159\n";
index = i;
char k;
cout << "Press Enter to continue";
cin >> k;
}
}
cout << "The " << index << "th approximation begins with 3.14159\n";
return 0;
}
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