"Read XML" Code Answer's
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read xml file c#
Concerned Copperhead
on Jun 11, 2020
XmlDocument doc = new XmlDocument();
using (StreamReader streamReader = new StreamReader(path_name, Encoding.UTF8))
{
contents = streamReader.ReadToEnd();
}
doc.LoadXml(contents);Read XML
Awful Ant
on May 15, 2021
from bs4 import BeautifulSoup
soup = BeautifulSoup(open('W2Testfile.xml', encoding='utf-8'), 'lxml')
# Just copy from and doc and lower search or write lower case
sub_id = soup.find('SubmissionId'.lower())
# Tag and text
print(sub_id)
print(sub_id.text)
#---| Take out part eg doc 2,then <find_all> of a tag that there are several of
doc_2 = soup.find('returndata', {'documentcnt': '2'})
dep_detail = doc_2.find_all('DependentDetail'.lower())
print('-' * 30)
print(dep_detail[0].find('dependentrelationshipcd'))
print(dep_detail[0].find('dependentrelationshipcd').text)
Source: python-forum.io
how to read an xml file
TheRubberDucky
on Sep 15, 2020
import xmltodict as xtd
import os
xml_file_content = ""
catalog_dir = os.chdir('directory')
catalog_dir_array = os.listdir(catalog_dir)
if("nameOfFile.xml" in catalog_dir_array):
catalog_file_content = open("nameOfFile.xml", "r").read()
catalog_file_content_dict = xtd.parse(catalog_file_content)All those coders who are working on the C# based application and are stuck on Read XML can get a collection of related answers to their query. Programmers need to enter their query on Read XML related to C# code and they'll get their ambiguities clear immediately. On our webpage, there are tutorials about Read XML for the programmers working on C# code while coding their module. Coders are also allowed to rectify already present answers of Read XML while working on the C# language code. Developers can add up suggestions if they deem fit any other answer relating to "Read XML". Visit this developer's friendly online web community, CodeProZone, and get your queries like Read XML resolved professionally and stay updated to the latest C# updates.
