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dart regex

By Hilarious HorseHilarious Horse on Apr 03, 2020 
RegExp exp = new RegExp(r"(\w+)");
String str = "Parse my string";
Iterable<RegExpMatch> matches = exp.allMatches(str);

Source: api.dart.dev

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regex dart

By Homely HamerkopHomely Hamerkop on Oct 29, 2020 
RegExp regExp = new RegExp(
  r"/^WS{1,2}:\/\/\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}:56789/i",
  caseSensitive: false,
  multiLine: false,
);
print("allMatches : "+regExp.allMatches("WS://127.0.0.1:56789").toString());
print("firstMatch : "+regExp.firstMatch("WS://127.0.0.1:56789").toString());
print("hasMatch : "+regExp.hasMatch("WS://127.0.0.1:56789").toString());
print("stringMatch : "+regExp.stringMatch("WS://127.0.0.1:56789").toString());

allMatches : ()
firstMatch : null
hasMatch : false
stringMatch : null

Source: stackoverflow.com

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0

dart regex,regex dart

By Distinct DolphinDistinct Dolphin on Apr 24, 2021 
// Here's a regular expression for one or more digits.
var numbers = RegExp(r'\d+');

var allCharacters = 'llamas live fifteen to twenty years';
var someDigits = 'llamas live 15 to 20 years';

// contains() can use a regular expression.
assert(!allCharacters.contains(numbers));
assert(someDigits.contains(numbers));

// Replace every match with another string.
var exedOut = someDigits.replaceAll(numbers, 'XX');
assert(exedOut == 'llamas live XX to XX years');

Source: dart.dev

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