"image upload" Code Answer's
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upload picture
Undefined
on Jun 11, 2021
<input type="file" id="fileinput" name ="image" multiple="multiple" accept="image/*" />display image with file upload
EzeeMax
on Jun 12, 2020
<head>
<title>Image Upload</title>
<style>
body {
margin:0px;
}
.center {
display:inline;
margin: 3px;
}
.form-input {
width:100px;
padding:3px;
background:#fff;
border:2px dashed dodgerblue;
}
.form-input input {
display:none;
}
.form-input label {
display:block;
width:100px;
height: auto;
max-height: 100px;
background:#333;
border-radius:10px;
cursor:pointer;
}
.form-input img {
width:100px;
height: 100px;
margin: 2px;
opacity: .4;
}
.imgRemove{
position: relative;
bottom: 114px;
left: 68%;
background-color: transparent;
border: none;
font-size: 30px;
outline: none;
}
.imgRemove::after{
content: ' \21BA';
color: #fff;
font-weight: 900;
border-radius: 8px;
cursor: pointer;
}
.small{
color: firebrick;
}
</style>
</head>
<body>
<div class="image-upload-one">
<div class="center">
<div class="form-input">
<label for="file-ip-1">
<img id="file-ip-1-preview" src="https://i.ibb.co/ZVFsg37/default.png">
<button type="button" class="imgRemove" onclick="myImgRemoveFunctionOne()"></button>
</label>
<input type="file" name="img_one" id="file-ip-1" accept="image/*" onchange="showPreviewOne(event);">
</div>
<small class="small">Use the ↺ icon to reset the image</small>
</div>
</div>
<script>
function showPreviewOne(event){
if(event.target.files.length > 0){
let src = URL.createObjectURL(event.target.files[0]);
let preview = document.getElementById("file-ip-1-preview");
preview.src = src;
preview.style.display = "block";
}
}
function myImgRemoveFunctionOne() {
document.getElementById("file-ip-1-preview").src = "https://i.ibb.co/ZVFsg37/default.png";
}
</script>
</body>Source: codepen.io
image upload
<input type="file" id="fileinput" name ="image" multiple="multiple" accept="image/*" />
Source: stackoverflow.com
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