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merge sort
adriancmiranda
on May 31, 2020
// @see https://www.youtube.com/watch?v=es2T6KY45cA&vl=en
// @see https://www.cs.usfca.edu/~galles/visualization/ComparisonSort.html
function merge(list, start, midpoint, end) {
const left = list.slice(start, midpoint);
const right = list.slice(midpoint, end);
for (let topLeft = 0, topRight = 0, i = start; i < end; i += 1) {
if (topLeft >= left.length) {
list[i] = right[topRight++];
} else if (topRight >= right.length) {
list[i] = left[topLeft++];
} else if (left[topLeft] < right[topRight]) {
list[i] = left[topLeft++];
} else {
list[i] = right[topRight++];
}
}
}
function mergesort(list, start = 0, end = undefined) {
if (end === undefined) {
end = list.length;
}
if (end - start > 1) {
const midpoint = ((end + start) / 2) >> 0;
mergesort(list, start, midpoint);
mergesort(list, midpoint, end);
merge(list, start, midpoint, end);
}
return list;
}
mergesort([4, 7, 2, 6, 4, 1, 8, 3]);merge sort algo
Innocent Iguana
on Jul 09, 2020
def mergeSort(arr):
if len(arr) >1:
mid = len(arr)//2 # Finding the mid of the array
L = arr[:mid] # Dividing the array elements
R = arr[mid:] # into 2 halves
mergeSort(L) # Sorting the first half
mergeSort(R) # Sorting the second half
i = j = k = 0
# Copy data to temp arrays L[] and R[]
while i < len(L) and j < len(R):
if L[i] < R[j]:
arr[k] = L[i]
i+= 1
else:
arr[k] = R[j]
j+= 1
k+= 1
# Checking if any element was left
while i < len(L):
arr[k] = L[i]
i+= 1
k+= 1
while j < len(R):
arr[k] = R[j]
j+= 1
k+= 1
# Code to print the list
def printList(arr):
for i in range(len(arr)):
print(arr[i], end =" ")
print()
# driver code to test the above code
if __name__ == '__main__':
arr = [12, 11, 13, 5, 6, 7]
print ("Given array is", end ="\n")
printList(arr)
mergeSort(arr)
print("Sorted array is: ", end ="\n")
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