"$.ajax({" Code Answer's

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ajax exmaple\

By Disturbed DogDisturbed Dog on Oct 17, 2020
$.ajax({
    url:'your url',
    type: 'POST',  // http method
    data: { myData: 'This is my data.' },  // data to submit
    success: function (data, status, xhr) { // after success your get data
        $('p').append('status: ' + status + ', data: ' + data);
    },
    error: function (jqXhr, textStatus, errorMessage) { // if any error come then 
            $('p').append('Error' + errorMessage);
    }
});

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6

jquery ajax

By Jerome ChooJerome Choo on Feb 15, 2021
    $.ajax({
        url: url,
        dataType: "json",
        type: "Post",
        async: true,
        data: { },
        success: function (data) {
           
        },
        error: function (xhr, exception) {
            var msg = "";
            if (xhr.status === 0) {
                msg = "Not connect.\n Verify Network." + xhr.responseText;
            } else if (xhr.status == 404) {
                msg = "Requested page not found. [404]" + xhr.responseText;
            } else if (xhr.status == 500) {
                msg = "Internal Server Error [500]." +  xhr.responseText;
            } else if (exception === "parsererror") {
                msg = "Requested JSON parse failed.";
            } else if (exception === "timeout") {
                msg = "Time out error." + xhr.responseText;
            } else if (exception === "abort") {
                msg = "Ajax request aborted.";
            } else {
                msg = "Error:" + xhr.status + " " + xhr.responseText;
            }
           
        }
    }); 

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0

ajax syntax in javascript

By Mysterious GirlMysterious Girl on Sep 30, 2020
var id = empid;

$.ajax({
    type: "POST",
    url: "../Webservices/EmployeeService.asmx/GetEmployeeOrders",
    data: "{empid: " + empid + "}",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: function(result){
        alert(result.d);
        console.log(result);
    }
});

Source: stackoverflow.com

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3

jquery ajax

By Joyous JaguarJoyous Jaguar on May 05, 2020
 $.ajax({

   url     : "file.php",
   method  : "POST",

       data: { 
         //key                      :   value 
         action                   	:   action , 
         key_1   					:   value_key_1,
         key_2   					:   value_key_2
       }
   })

   .fail(function() { return false; })
	// Appel OK
   .done(function(data) {

   console.log(data);

 });

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13

$.ajax({

By Shiny SkipperShiny Skipper on Mar 15, 2021
<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>jQuery.post demo</title>
  <script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
 
<form action="/" id="searchForm">
  <input type="text" name="s" placeholder="Search...">
  <input type="submit" value="Search">
</form>
<!-- the result of the search will be rendered inside this div -->
<div id="result"></div>
 
<script>
// Attach a submit handler to the form
$( "#searchForm" ).submit(function( event ) {
 
  // Stop form from submitting normally
  event.preventDefault();
 
  // Get some values from elements on the page:
  var $form = $( this ),
    term = $form.find( "input[name='s']" ).val(),
    url = $form.attr( "action" );
 
  // Send the data using post
  var posting = $.post( url, { s: term } );
 
  // Put the results in a div
  posting.done(function( data ) {
    var content = $( data ).find( "#content" );
    $( "#result" ).empty().append( content );
  });
});
</script>
 
</body>
</html>

Source: www.freecodecamp.org

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0

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