"django create view filter options" Code Answer's
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django create view filter options
class FolderCreate(CreateView):
template_name = 'Form/folder_create.html'
form_class = FolderForm
def get_form_kwargs(self):
kwargs = super(FolderCreate, self).get_form_kwargs()
kwargs['user'] = self.request.user
return kwargs
Source: stackoverflow.com
django create view filter options
class FolderForm(forms.ModelForm):
class Meta:
model = Folder
fields = ['name', 'parent']
def __init__(self, *args, **kwargs):
user = kwargs.pop('user')
super(FolderForm, self).__init__(*args, **kwargs)
self.fields['parent'].queryset = Folder.objects.filter(user=user)
Source: stackoverflow.com
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