"longest consecutive subsequence" Code Answer's
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python longest consecutive sequence
def longest(seq = input("""Please enter a series of random letters,
i will guess the largest sequence of letters in order""").upper()):
max_count = 0
max_char = ""
prev_char = ""
for current in seq:
if prev_char == current:
count += 1
else:
count = 1
if count > max_count:
max_count = count
max_char = current
prev_char = current
print(max_char,max_count)
longest()
longest common subsequence
class Solution:
def longestCommonSubsequence(self, text1: str, text2: str) -> int:
"""
text1: horizontally
text2: vertically
"""
dp = [[0 for _ in range(len(text1)+1)] for _ in range(len(text2)+1)]
for row in range(1, len(text2)+1):
for col in range(1, len(text1)+1):
if text2[row-1]==text1[col-1]:
dp[row][col] = 1+ dp[row-1][col-1]
else:
dp[row][col] = max(dp[row-1][col], dp[row][col-1])
return dp[len(text2)][len(text1)]
longest common subsequence
int maxSubsequenceSubstring(char x[], char y[],
int n, int m)
{
int dp[MAX][MAX];
// Initialize the dp[][] to 0.
for (int i = 0; i <= m; i++)
for (int j = 0; j <= n; j++)
dp[i][j] = 0;
// Calculating value for each element.
for (int i = 1; i <= m; i++) {
for (int j = 1; j <= n; j++) {
// If alphabet of string X and Y are
// equal make dp[i][j] = 1 + dp[i-1][j-1]
if (x[j - 1] == y[i - 1])
dp[i][j] = 1 + dp[i - 1][j - 1];
// Else copy the previous value in the
// row i.e dp[i-1][j-1]
else
dp[i][j] = dp[i][j - 1];
}
}
// Finding the maximum length.
int ans = 0;
for (int i = 1; i <= m; i++)
ans = max(ans, dp[i][n]);
return ans;
}
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