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how many sets of 3 in 4

Yellowed Yak on Apr 10, 2020

nCr = n!/(r!(n-r)!)
4C3 = 4!/(3!(4-3)!)
    = 24/(6*1)
    = 4

Source: math.stackexchange.com

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"how many sets of 3 in 4" Code Answer's