"dot product" Code Answer's
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dot product ocaml
JunJun
on Oct 06, 2020
let rec safe_dot_product (vect1: int list) (vect2: int list) : int option =
match (vect1, vect2) with
| [],[] -> Some 0
| [],_ -> None
| _,[] -> None
| (x::xs, y::ys) ->
match safe_dot_product xs ys with
| None -> None
| Some m -> Some ((x*y) + m)dot product python
Bored Coder
on Apr 17, 2020
A = [1,2,3,4,5,6]
B = [2,2,2,2,2,2]
# with numpy
import numpy as np
np.dot(A,B) # 42
np.sum(np.multiply(A,B)) # 42
#Python 3.5 has an explicit operator @ for the dot product
np.array(A)@np.array(B)# 42
# without numpy
sum([A[i]*B[i] for i in range(len(B))]) # 42Source: stackoverflow.com
dot product
Saf1
on Apr 05, 2021
Let a be a vector with coordinates (a1, a2, a3)
Let b be a vector with coordinates (b1, b2, b3)
Dot Product:
<a1, a2, a3> • <b1, b2, b3> = a1*b1 + a2*b2 + a3*b3
a • b = |a||b|cosθ, where θ is the angle between the two vectorsnumpy dot product
Old-fashioned Okapi
on Mar 26, 2020
a = np.array([[1,2],[3,4]])
b = np.array([[11,12],[13,14]])
np.dot(a,b)
[[37 40], [85 92]] dot product array
Long Lark
on Jun 21, 2020
import numpy.matlib
import numpy as np
a = np.array([[1,2],[3,4]])
b = np.array([[11,12],[13,14]])
np.dot(a,b)Source: www.tutorialspoint.com
r dot product
Trustworthy Whale
on Dec 30, 2020
a = c(1,2)
b = c(0,1)
# Perform the dot product
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