"floyd tortoise and hare" Code Answer's
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floyd tortoise and hare
nodes = [(1, 2), (2, 3), (3, 4), (4, 5), (5, 2)]
def next(parent):
def find(nodes, parent):
current = nodes[0]
rest = nodes[1:]
if current and current[0] == parent:
return current[1]
else:
return find(rest, parent)
return find(nodes, parent)
def next_next(x):
return next(next(x))
def meet(slow, fast, p1, p2, steps):
p1 = slow(p1)
p2 = fast(p2)
steps = steps + 1
if p1 == p2:
return (p1, steps)
else:
return meet(slow, fast, p1, p2, steps)
def meet_result(slow, fast, p1, p2):
result = meet(slow, fast, p1, p2, 0)
return result[0]
def meet_count(slow, fast, p1, p2):
result = meet(slow, fast, p1, p2, 0)
return result[1]
def find_cycle(init):
cycle_meet = meet_result(next, next_next, init, init)
cycle_root = meet_result(next, next, cycle_meet, init)
cycle_length = meet_count(lambda x: x, next, cycle_root, cycle_root)
return (cycle_meet, cycle_root, cycle_length)
Source: kimsereylam.com
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