"warshall algorithm transitive closure calculator" Code Answer's
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warshall algorithm transitive closure calculator
def transitiveClosure (matrix):
result = ""
length = len(matrix)
for k in range(0, length):
for row in range(0, length):
for col in range(0, length):
matrix[row] [col] = matrix[row][col] or (matrix[row][k] and matrix[k][col])
result += ("\n W" + str(k) +" is: \n" + str(matrix).replace("]," , "] \n") + "\n")
result += ("\n Transitive closure is \n" + str(matrix).replace("]," , "]\n"))
print result
return result
Source: rdxiang.github.io
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