"A static method avg High Temp() that receives no parameter" Code Answer's
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A static method avg High Temp() that receives no parameter
import java.util.*;
public class Temperature {
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
// Input the number of days from the user.
System.out.print("How many days' temperatures? ");
int days = console.nextInt( );
// Declare and create an array, maybe should check if days is positive
int[ ] temps = new int[days];
// Input and store the temperatures in the array
for (int i = 0; i < temps.length; i++) {
System.out.print("Day " + i + "'s high temp: ");
temps[i] = console.nextInt( );
}
// Calculate and print the average
int sum = 0;
for (int i = 0; i < temps.length; i++) {
sum += temps[i];
}
// need a cast to avoid integer division
double average = (double) sum / temps.length;
System.out.println("Average temp = " + average);
// Count the number of values that were above average
int count = 0;
for (int i = 0; i < temps.length; i++) {
if (temps[i] > average) {
count++;
}
}
System.out.println(count + " days were above average");
}
}
Source: www.cs.utsa.edu
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