"iterative segment tree codeforces" Code Answer's
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iterative segment tree codeforces
const int N = 1e5; // limit for array size
int n; // array size
int t[2 * N];
void build() { // build the tree
for (int i = n - 1; i > 0; --i) t[i] = t[i<<1] + t[i<<1|1];
}
void modify(int p, int value) { // set value at position p
for (t[p += n] = value; p > 1; p >>= 1) t[p>>1] = t[p] + t[p^1];
}
int query(int l, int r) { // sum on interval [l, r)
int res = 0;
for (l += n, r += n; l < r; l >>= 1, r >>= 1) {
if (l&1) res += t[l++];
if (r&1) res += t[--r];
}
return res;
}
int main() {
scanf("%d", &n);
for (int i = 0; i < n; ++i) scanf("%d", t + n + i);
build();
modify(0, 1);
printf("%d\n", query(3, 11));
return 0;
}
Source: codeforces.com
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