"subtract period dynamically from current time in mule" Code Answer's
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subtract period dynamically from current time in mule
%dw 2.0
output application/json
var numberOfDays = 3
---
{
oneDayBefore: |2019-10-01T23:57:59Z| - |P1D|,
threeDaysBefore: |2019-10-01T23:57:59Z| - ("P$(numberOfDays)D" as Period),
a: |2019-10-01| - |P1Y|,
b: |P1Y| - |2019-10-01|,
c: |2019-10-01T23:57:59Z| - |P1Y|,
d: |2019-10-01T23:57:59Z| + |P1Y|,
e: |2019-10-01T23:57:59| - |P1Y|,
f: |PT9M| - |23:59:56|,
g: |23:59:56| + |PT9M|,
h: |23:59:56-03:00| - |PT9M|,
u: |23:59:56-03:00| - |22:59:56-03:00|,
j: |23:59:56-03:00| - |22:59:56-00:00|,
k: |2019-10-01T23:57:59| - |P2Y9M1D| - |PT57M59S| + |PT2H|,
l: |23:59:56| - |22:59:56|,
o: |2019-10-01| - |2018-09-23|,
p: |2019-10-01T23:57:59Z| - |2018-10-01T23:57:59Z|,
q: |2019-10-01T23:57:59| - |2018-10-01T23:57:59|
}
Source: docs.mulesoft.com
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