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longest increasing subsequence techie delight
Xanthous Xenomorph
on Jul 02, 2020
#include <iostream>
#include <vector>
using namespace std;
// Iterative function to find longest increasing subsequence
// of given array
void findLIS(int arr[], int n)
{
// LIS[i] stores the longest increasing subsequence of subarray
// arr[0..i] that ends with arr[i]
vector<int> LIS[n];
// LIS[0] denotes longest increasing subsequence ending with arr[0]
LIS[0].push_back(arr[0]);
// start from second element in the array
for (int i = 1; i < n; i++)
{
// do for each element in subarray arr[0..i-1]
for (int j = 0; j < i; j++)
{
// find longest increasing subsequence that ends with arr[j]
// where arr[j] is less than the current element arr[i]
if (arr[j] < arr[i] && LIS[j].size() > LIS[i].size())
LIS[i] = LIS[j];
}
// include arr[i] in LIS[i]
LIS[i].push_back(arr[i]);
}
// uncomment below lines to print contents of vector LIS
/* for (int i = 0; i < n; i++)
{
cout << "LIS[" << i << "] - ";
for (int j : LIS[i])
cout << j << " ";
cout << endl;
} */
// j will contain index of LIS
int j;
for (int i = 0; i < n; i++)
if (LIS[j].size() < LIS[i].size())
j = i;
// print LIS
for (int i : LIS[j])
cout << i << " ";
}
int main()
{
int arr[] = { 0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15 };
int n = sizeof(arr)/sizeof(arr[0]);
findLIS(arr, n);
return 0;
}
Source: www.techiedelight.com
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