cout does not name a type error Solution

cout is a built-in function that outputs text and/or binary data. It is used to display information on the screen, such as a line of text or an image. In C++, cout returns a general output stream object (std::ostream) called cout. This can be used to print characters, numbers, and strings. cout does not name a type means that cout function is not declared under the scope. to solve this problem first method that is helpful would be declaring the function prototype before the main() method. So, we have used the function prototype before the main method in the updated code.

cout does not name a type

Upset Unicorn on Jun 17, 2020

//Statements in C++ need to be inside of a function
int main(){
	std::cout << "Hello World" << std::endl;
    //Works because we are inside of a function
}
std::cout << "Hello World" << std::endl;
//Doesn't work because we are not inside of a function

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cout is a type. The std::cout class is a type that contains a stream of characters.cout is not a type. cout is an object of the std::cout class, which contains a stream of characters.

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cout does not name a type error Solution