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substitution failure is not an error

Ty Rymer on Mar 23, 2020

/* "Substitution Failure Is Not An Error"

This rule applies during overload resolution of function templates:
When substituting the explicitly specified or deduced type for the
template parameter fails, the specialization is discarded from the
overload set instead of causing a compile error.

This feature is used in template metaprogramming.
STL features like std::enable_if use SFINAE
*/

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"substitution failure is not an error" Code Answer's