"binary tree search" Code Answer's
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binary tree search
/* This is just the seaching function you need to write the required code.
Thank you. */
void searchNode(Node *root, int data)
{
if(root == NULL)
{
cout << "Tree is empty\n";
return;
}
queue<Node*> q;
q.push(root);
while(!q.empty())
{
Node *temp = q.front();
q.pop();
if(temp->data == data)
{
cout << "Node found\n";
return;
}
if(temp->left != NULL)
q.push(temp->left);
if(temp->right != NULL)
q.push(temp->right);
}
cout << "Node not found\n";
}
binary search tree
Binary Search Tree is a node-based binary tree data structure which has the following properties:
The left subtree of a node contains only nodes with keys lesser than the node’s key.
The right subtree of a node contains only nodes with keys greater than the node’s key.
The left and right subtree each must also be a binary search tree.
binary search tree
# Driver Code
arr = [ 2, 3, 4, 10, 40 ]
x = 10
# Function call
result = binarySearch(arr, 0, len(arr)-1, x)
if result != -1:
print ("Element is present at index % d" % result)
else:
print ("Element is not present in array")
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