"typescript read url search params" Code Answer's
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generate query string from urlsearchparams
URLSearchParams.toString()
Source: developer.mozilla.org
get url params in typescript
import {Router, ActivatedRoute, Params} from '@angular/router';
import {OnInit, Component} from '@angular/core';
@Component({...})
export class MyComponent implements OnInit {
constructor(private activatedRoute: ActivatedRoute) {}
ngOnInit() {
// Note: Below 'queryParams' can be replaced with 'params' depending on your requirements
this.activatedRoute.queryParams.subscribe(params => {
const userId = params['userId'];
console.log(userId);
});
}
}
Source: stackoverflow.com
typescript read url search params
const product = urlParams.get('product')
console.log(product);
// shirt
const color = urlParams.get('color')
console.log(color);
// blue
const newUser = urlParams.get('newuser')
console.log(newUser);
// empty string
Source: www.sitepoint.com
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