"**kwargs python" Code Answer's
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args kwargs python
>>> def argsKwargs(*args, **kwargs):
... print(args)
... print(kwargs)
...
>>> argsKwargs('1', 1, 'slgotting.com', upvote='yes', is_true=True, test=1, sufficient_example=True)
('1', 1, 'slgotting.com')
{'upvote': 'yes', 'is_true': True, 'test': 1, 'sufficient_example': True}
**kwargs
When it iterating over a dictionary you are only able to iterate over
the keys not the values. The ** when placed before a variable will allow
you to iterate and unpack both key and value pairs. Because you are
unpacking both key and value this will return the result as a dictionary.
python *arg **kwargs
>>> def f(a, b, *args, **kwargs):
... print(F'a = {a}')
... print(F'b = {b}')
... print(F'args = {args}')
... print(F'kwargs = {kwargs}')
...
>>> f(1, 2, 'foo', 'bar', 'baz', 'qux', x=100, y=200, z=300)
a = 1
b = 2
args = ('foo', 'bar', 'baz', 'qux')
kwargs = {'x': 100, 'y': 200, 'z': 300}
Source: realpython.com
*args,**kwarg
def intro(**data):
print("\nData type of argument:",type(data))
for key, value in data.items():
print("{} is {}".format(key,value))
intro(Firstname="Sita", Lastname="Sharma", Age=22, Phone=1234567890)
intro(Firstname="John", Lastname="Wood", Email="[email protected]", Country="Wakanda", Age=25, Phone=9876543210)
Source: www.programiz.com
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