"UserModel._default_manager.filter(**{case_insensitive_username_field:username}).exists()):" Code Answer's

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UserModel._default_manager.filter(**{case_insensitive_username_field:username}).exists()):

By Evil EagleEvil Eagle on Apr 03, 2021
AUTH_USER_MODEL = 'core.CustomUser'

Source: simpleisbetterthancomplex.com

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