"Find duplicate rows in a 5x5 Matrix." Code Answer's
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Find duplicate rows in a 5x5 Matrix.
# A class representing a node:
class Trie:
# Constructor
def __init__(self):
self.character = [None] * 2
# set when node is a leaf node
self.isLeaf = False
# Iterative function to insert list in Trie.
def insert(head, A):
# start from root node
curr = head
for i in A:
# create a node if path doesn't exists
if curr.character[i] is None:
curr.character[i] = Trie()
# go to next node
curr = curr.character[i]
# if row is inserted before, return false
if curr.isLeaf:
return False
# mark leaf node and return True
curr.isLeaf = True
return True
if __name__ == '__main__':
mat = [
[1, 0, 0, 1, 0],
[0, 1, 1, 0, 0],
[1, 0, 0, 1, 0],
[0, 0, 1, 1, 0],
[0, 1, 1, 0, 0]
]
# insert all rows of into trie
head = Trie()
for i, e in enumerate(mat):
if not insert(head, e):
print(f"Duplicate row found: Row #{i+1}")
Source: www.techiedelight.com
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