"Given a square matrix list of order 'n'. The maximum value possible for 'n' is 20." Code Answer's

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Given a square matrix list[ ] [ ] of order 'n'. The maximum value possible for 'n' is 20.

Creepy Caiman on Aug 27, 2020

import java.util.*;
class ISCprac2008q03{
public static void main(String args[])
throws InputMismatchException{
Scanner scan=new Scanner(System.in);

System.out.println("Enter the number of rows(<=20) for the square matrix : ");
int n=scan.nextInt();

if(n>20)
    System.out.println("Number must not exceed 20.");

else{
int a[][]=new int[n][n];
int i,j,rg,cg,rs,cs,s,g,k,t;

for(i=0;i< n;i++){
for(j=0;j< n;j++){
a[i][j] = scan.nextInt();
}
}

System.out.println("ORIGINAL MATRIX: ");
for(i=0;i< n;i++){
for(j=0;j< n;j++){
System.out.print(a[i][j] + " ");
}
System.out.println();
}
s = g = a[0][0];
rg=cg=rs=cs=0;

for(i=0;i< n;i++){
for(j=0;j< n;j++){

//Condition to check smallest element
if(s > a[i][j]){
    s = a[i][j];
    rs = i;
    cs = j;
}
//Condition to check greatest element
if(g < a[i][j]){
    g = a[i][j];
    rg = i;
    cg = j;
}
}
}
for(i=0;i< n;i++){
for(j=0;j< n;j++){

for(k=j+1;k< n;k++){
    if(a[i][j] > a[i][k]){
        t = a[i][j];
        a[i][j] = a[i][k];
        a[i][k] = t;
    }
}

}
}
System.out.println("The largest element "+g+" is in row "+(rg+1)+" and column "+(cg+1));
System.out.println("The smallest element "+s+" is in row "+(rs+1)+" and column "+(cs+1));

System.out.println("SORTED MATRIX: ");
for(i=0;i< n;i++){
for(j=0;j< n;j++){
System.out.print(a[i][j] + " ");
}
System.out.println();
}

}//else

}//eom
}//eoc

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"Given a square matrix list of order 'n'. The maximum value possible for 'n' is 20." Code Answer's