"jquery replicate div on drag" Code Answer's
You're definitely familiar with the best coding language Javascript that developers use to develop their projects and they get all their queries like "jquery replicate div on drag" answered properly. Developers are finding an appropriate answer about jquery replicate div on drag related to the Javascript coding language. By visiting this online portal developers get answers concerning Javascript codes question like jquery replicate div on drag. Enter your desired code related query in the search bar and get every piece of information about Javascript code related question on jquery replicate div on drag.
jquery replicate div on drag
$('.draggable').draggable({
revert: "invalid",
stack: ".draggable",
helper: 'clone'
});
$('.droppable').droppable({
accept: ".draggable",
drop: function(event, ui) {
var droppable = $(this);
var draggable = ui.draggable;
// Move draggable into droppable
var drag = $('.droppable').has(ui.draggable).length ? draggable : draggable.clone().draggable({
revert: "invalid",
stack: ".draggable",
helper: 'clone'
});
drag.appendTo(droppable);
draggable.css({
float: 'left'
});
}
});
Source: stackoverflow.com
All those coders who are working on the Javascript based application and are stuck on jquery replicate div on drag can get a collection of related answers to their query. Programmers need to enter their query on jquery replicate div on drag related to Javascript code and they'll get their ambiguities clear immediately. On our webpage, there are tutorials about jquery replicate div on drag for the programmers working on Javascript code while coding their module. Coders are also allowed to rectify already present answers of jquery replicate div on drag while working on the Javascript language code. Developers can add up suggestions if they deem fit any other answer relating to "jquery replicate div on drag". Visit this developer's friendly online web community, CodeProZone, and get your queries like jquery replicate div on drag resolved professionally and stay updated to the latest Javascript updates.