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how can I sort a dictionary in python according to its values?

By ai-loverai-lover on Nov 23, 2020
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

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16

sort list of dictionaries by key python

By Stupid StorkStupid Stork on Mar 25, 2020
newlist = sorted(list_to_be_sorted, key=lambda k: k['name']) 

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9

sort a dictionary

By RazvanRazvan on Sep 24, 2020
from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

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1

how to sort a dictionary py

on May 18, 2021
orders = {
	'cappuccino': 54,
	'latte': 56,
	'espresso': 72,
	'americano': 48,
	'cortado': 41
}

sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)

for i in sort_orders:
	print(i[0], i[1])

Source: careerkarma.com

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0

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