"Insertion sort algorithm" Code Answer's
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insertion sort python
def insertionSort(alist):
for i in range(1,len(alist)):
#element to be compared
current = alist[i]
#comparing the current element with the sorted portion and swapping
while i>0 and alist[i-1]>current:
alist[i] = alist[i-1]
i = i-1
alist[i] = current
#print(alist)
return alist
print(insertionSort([5,2,1,9,0,4,6]))
java insertion sort
/**
* Insertion sort algorithm, O(n^2) time complexity.
*/
public static void insertionSort(int[] arr) {
int n = arr.length;
for(int i = 1; i < n; i++) {
int key = arr[i];
int j = i - 1;
//shift until you find the position to place the element 'key'
while(j >= 0 && arr[j] > key) {
arr[j+1] = arr[j];
j--;
}
//place element 'key' in the correct position in the sorted part of the array
arr[j+1] = key;
}
}
insertion sort python
def insertion_sort(lst):
for i in range(1,len(lst)):
while i > 0 and lst[i - 1] >lst[i] :
lst[i - 1], lst[i] = lst[i] , lst[i - 1]
## swapping
i = i -1
return lst
print(insertion_sort([4,2,2,3,4,3,1,1,1,2]))
insertion sort java
Insertion program
public class InsertionSortExample
{
public void sort(int[] arrNum)
{
int number = arrNum.length;
for(int a = 1; a < number; ++a)
{
int keyValue = arrNum[a];
int b = a - 1;
while(b >= 0 && arrNum[b] > keyValue)
{
arrNum[b + 1] = arrNum[b];
b = b - 1;
}
arrNum[b + 1] = keyValue;
}
}
static void displayArray(int[] arrNum)
{
int num = arrNum.length;
for(int a = 0; a < num; ++a)
{
System.out.print(arrNum[a] + " ");
}
System.out.println();
}
public static void main(String[] args)
{
int[] arrInput = { 50, 80, 10, 30, 90, 60 };
InsertionSortExample obj = new InsertionSortExample();
obj.sort(arrInput);
displayArray(arrInput);
}
}
Source: www.flowerbrackets.com
insertion sort
def insertionSort(arr):
for i in range(1, len(arr)):
key = arr[i]
j = i-1
while j >= 0 and key < arr[j] :
arr[j + 1] = arr[j]
j -= 1
arr[j + 1] = key
Insertion sort algorithm
INSERTION-SORT(A)
for i = 1 to n
key ← A [i]
j ← i – 1
while j > = 0 and A[j] > key
A[j+1] ← A[j]
j ← j – 1
End while
A[j+1] ← key
End for
Source: www.interviewbit.com
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