"how to sort a dictionary" Code Answer's
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how can I sort a dictionary in python according to its values?
ai-lover
on Nov 23, 2020
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)python dict sort by value
Jealous Jellyfish
on May 18, 2020
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}Source: stackoverflow.com
sort the dictionary in python
Clean Cicada
on Jul 18, 2020
d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)python sort dict by key
IJustWannaHelp
on Oct 15, 2020
A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}
output:
{-1: 4, 1: 2, 4: -20}python get dictionary keys sorted by value
Delta Sierra
on Oct 10, 2020
sorted(A, key=A.get)how to sort a dictionary
Frantic Ferret
on May 24, 2021
markdict = {"Tom":67, "Tina": 54, "Akbar": 87, "Kane": 43, "Divya":73}
marklist = sorted(markdict.items(), key=lambda x:x[1])
sortdict = dict(marklist)
print(sortdict)
Source: www.tutorialsteacher.com
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